27p^2-p=0

Solution for 27p^2-p=0 equation:

27p^2-p=0

We add all the numbers together, and all the variables

27p^2-1p=0

a = 27; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·27·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*27}=\frac{0}{54}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*27}=\frac{2}{54}
=1/27
$